(6x^2-7x+2)/(3x-2)
来源:百度知道 编辑:UC知道 时间:2024/09/21 04:33:16
(6x^2-7x+2)/(3x-2)
分析6x^2-7x+2
十字相乖法
6X^2分解为 2x 3x 的积
常数项2分解为 -1 -2 的积
上面的交叉项“十字”方向的项相乖
即 2x *(-2)+ 3x* (-1)= -7x (等中间项)
所以
6x^2-7x+2
=(2X-1)(3X-2)
原式
=(2x-1)(3x-2)/(3x-2)
=2x-1
(6x^2-7x+2)/(3x-2)=(3x-2)(2x+1)/(3x-2)=2x+1
用十字相乘法:
(6x^2-7x+2)/(3x-2)
=(2x-1)(3x-2)/(3x-2)
=(2x-1)
2x-1
5x/(x^2+x-6)+(2x-5)/(x^2-x-12)=(7x-10)/(x^2-6x+8)
(x+1/x+2)-(1/x+7)=(x+2/x+3)-(1/x+6)
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解下列分式方程:(1)X/(X-2)+(X-9)/(X-7)=(X+1)/(X-1)+(X-8)/(X-6)(2)
x-5/x-7+x-2/x--4=x-3/x-5+x-4/x-6
方程(x+2)/(x+1)-(x+4)/(x+3)=(x+6)/(x+5)-(x+8)/(x+7)
2(x^2+1)/x+1 + 6(x+1)/x^2+1 =7
解方程:2(x+1)/x+3+6(x+3)/(x-1)=7
(x^2+2x-3)/(x^2-9)*(x^2-5x+6)/(3x^2-x-2)
x-1/x^2+3x+2+6/2+x-x^2-10-x/4-x^2